Interoperability Testing,
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URL: http://forum.onestoptesting.com/forum_posts.asp?TID=360
Printed Date: 25Feb2025 at 6:41am
Topic: Interoperability Testing,
Posted By: vidhya
Subject: Interoperability Testing,
Date Posted: 28Mar2007 at 5:38am
Interoperability Testing
Interoperability testing is the activity of proving that end-to-end
functionality between (at least) two systems
(application/communicating) is as required by those base systems'
standards.
The important factors characterizing interoperability testing are:
●the Equipment Under Test (EUT) and the Qualified Equipment (QE) together define the boundaries for testing;
●the EUT and QE come from different suppliers (or, at least, different product lines);
●interoperability tests are performed at interfaces that offer only normal user control and observation;
●interoperability tests are based on functionality as experienced
by a user (i.e., they are not specified at the protocol level). In this context a user may be human or a software application;
●the tests are performed and observed at functional interfaces
such as Man-Machine Interfaces (MMIs), protocol service interfaces and
Application Programming Interfaces (APIs).
The fact that interoperability tests are performed at the end points
and at functional interfaces means that interoperability test cases can
only specify functional behaviour. They cannot explicitly cause or test
protocol error behaviour.
Mutual Testing
Mutation testing is verifying the testing procedure itself. It may also
be used to predict how many issues are yet to be found within the
system. To conduct Mutation testing one needs to purposely seed some
issues into the product (beware to remember each one). The amount of
found seeded defects indicates the level of testing coverage.
Verifying testing thoroughness
Suppose you have seeded 10 issues into different parts of system
and then provided it to the next testing stage. After completing
testing stage you have found 100 issues, 8 of which are from the seeded
sample. This means that defect removal efficiency of this stage is
about 80%.
DRE = DTF / DTS = 8 / 10 = 0.8
DRE - Defects removal efficiency
DS - Defects seeded
DSF - Seeded defects found
Determining the total amount of defect (including not found)
With example above, knowing that you have found 8 of 10 seeded
issues enables you to suppose that the total amount is proportional to
the amount of found issue at about the same ratio. Building a simple
proportion will give you a formula for determining the total amount of
defects:
DT = DTF * DS / DSF = 100 * 10 / 8 = 125
DT - Total defects (predicted)
This means you've got about 25 issues remaining not found.
Determining areas of weak coverage
Another possible application of this method is indicating the areas
when you would probably require more testing. Just look where, what
part of product, the not-found-seeded-issues are and add tests to those
areas. _________________ http://www.homeoftester.com/viewtopic.php?t=214 -
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